Thiele's method is to choose an alignment based on QT.
Alignment
Box design
Order
No
Type
Ripple(dB)
f3/fs
fB/fs
VB/VAS
QT
Quasi Third Order
1
QB3
---
2.68
2.000
0.0954
0.180
2
QB3
---
2.28
1.730
0.1337
0.209
3
QB3
---
1.77
1.420
0.2242
0.259
4
QB3
---
1.45
1.230
0.3390
0.303
Fourth Order
5
B4
---
1.000
1.000
0.7072
0.383 optimally flat
6
C4
---
0.867
0.927
0.9479
0.415
7
C4
0.13
0.729
0.829
1.372
0.446
8
C4
0.25
0.641
0.757
1.790
0.518
9
C4
0.55
0.600
0.716
2.062
0.557
9.5
C4
1.52
0.520
0.638
2.60
0.625
Tuning Lv
Calculate change of Speed of Sound in fibrous material
c=
speed of sound in air = 344 meters or 1128.6 feet
c'=
speed of sound in long fiber wool
P=
packing density of the fibrous material = 8kg/m3
New Qts with series inductor
Attenuation Circuit
Impedance Equalization Circuit (Zobel)
An Impedance Equalization Circuit is used to counteract the rising impedance of a voice coil caused by inductive reactance. The cause of this impedance rise is due to the speaker's voice coil inductance (Le).
Example:
For a midwoofer you calculate a Lowpass Butterworth 2nd order filter with a cutoff frequency at 4.5 kHz with the nominal impedance Re (from datasheet) of 6.0 ohm
The calculated inductor is 0.21 mH for 4.5 kHz cutoff frequency.
Impedancecurve Fullrange driver without compensation measuredimpeqalize measured with ARTA - LIMP
Take a look at the impedance plot of this fullrange driver. The impedance at 4.5 kHz is not 6.0 ohm, but 9.3 ohm!
At this impedance you inductor has to be 0.33 mH and not 0.21 mH.
This wrong inductor of 0.21 mH would create a crossover frequency of 2.9 kHz and not as assumed a crossover point of 4.5 kHz!
The importance to use impedance compensation should be clear now...
Re =
Ohms
R =
Ohms
Le =
mH
C =
uf
Advantage: the crossover filter works better, because the driver impedance is more stable.
Impedancecurve Fullrange driver with compensation measured with ARTA - LIMP